27 g of Al will react completely with how much mass of O2, to produce Al2O3?
27 g of Al= 1 mole of Al
Balance this equation
4Al + 3O2 → 2Al2O3
Mole ratio
Al : O2
4 : 3
1 : 3/4
Mass of O2 = 3/4 × 32 = 24g
27 g of Al= 1 mole of Al
Balance this equation
4Al + 3O2 → 2Al2O3
Mole ratio
Al : O2
4 : 3
1 : 3/4
Mass of O2 = 3/4 × 32 = 24g
